α	0°	30°	45°	60°	90°	120°	135°	150°	180°
sin α	$0$	$\frac{1}{2}$	$\frac{\sqrt{2}}{2}$	$\frac{\sqrt{3}}{2}$	$1$	$\frac{\sqrt{3}}{2}$	$\frac{\sqrt{2}}{2}$	$\frac{1}{2}$	$0$
cos α	$1$	$\frac{\sqrt{3}}{2}$	$\frac{\sqrt{2}}{2}$	$\frac{1}{2}$	$0$	$-\frac{1}{2}$	$-\frac{\sqrt{2}}{2}$	$-\frac{\sqrt{3}}{2}$	$-1$
tg α	$0$	$\frac{\sqrt{3}}{3}$	$1$	$\sqrt{3}$	$X$	$-\sqrt{3}$	$-1$	$-\frac{\sqrt{3}}{3}$	$0$

Zauważmy, że wartości dla  $0^{\circ },{90}^{\circ },{180}^{\circ }$   zostały podane na stronie 173.

 

$\sin {60}^{\circ }=\sin \left({180}^{\circ }-{60}^{\circ }\right)=\sin {120}^{\circ }=\frac{\sqrt{3}}{2}$  

$\cos {60}^{\circ }=-\cos \left({180}^{\circ }-{60}^{\circ }\right)=-\cos {120}^{\circ }=\frac{1}{2}$   

$\mathrm{tg}{60}^{\circ }=-\mathrm{tg}\left({180}^{\circ }-{60}^{\circ }\right)=-\mathrm{tg}{120}^{\circ }=\sqrt{3}$  

 

$\sin {135}^{\circ }=\sin \left({180}^{\circ }-{45}^{\circ }\right)=\sin {45}^{\circ }=\frac{\sqrt{2}}{2}$  

$\cos {135}^{\circ }=-\cos \left({180}^{\circ }-{135}^{\circ }\right)=-\cos {45}^{\circ }=-\frac{\sqrt{2}}{2}$   

$\mathrm{tg}{135}^{\circ }=-\mathrm{tg}\left({180}^{\circ }-{135}^{\circ }\right)=-\mathrm{tg}{45}^{\circ }=-1$  

 

$\sin {60}^{\circ }=\cos \left({90}^{\circ }-{60}^{\circ }\right)=\cos {30}^{\circ }=\frac{\sqrt{3}}{2}$  

$\cos {60}^{\circ }=\sin \left({90}^{\circ }-{60}^{\circ }\right)=\sin {30}^{\circ }=\frac{1}{2}$  

$\mathrm{tg}{60}^{\circ }=\mathrm{tg}\left({90}^{\circ }-{30}^{\circ }\right)=\frac{1}{\mathrm{tg}{30}^{\circ }}=\sqrt{3}$  

$\mathrm{tg}{30}^{\circ }=\frac{1}{\sqrt{3}}=\frac{\sqrt{3}}{3}$  

 

$\sin {150}^{\circ }=\sin \left({180}^{\circ }-{30}^{\circ }\right)=\sin {30}^{\circ }=\frac{1}{2}$  

$\cos {150}^{\circ }=\cos \left({180}^{\circ }-{30}^{\circ }\right)=-\cos {30}^{\circ }=-\frac{\sqrt{3}}{2}$  

$\mathrm{tg}{150}^{\circ }=\mathrm{tg}\left({180}^{\circ }-{30}^{\circ }\right)=-\mathrm{tg}{30}^{\circ }=-\frac{\sqrt{3}}{3}$