$obliczenia$

${\left(1\frac{3}{4}\right)}^2={\left(\frac{7}{4}\right)}^2=\frac{7}{4}\cdot \frac{7}{4}=\frac{49}{16}=3\frac{1}{16}$

${\left(1\frac{3}{4}\right)}^3={\left(\frac{7}{4}\right)}^3=\frac{7}{4}\cdot \frac{7}{4}\cdot \frac{7}{4}=\frac{49}{16}\cdot \frac{7}{4}=\frac{343}{64}=5\frac{23}{64}$

 

 

$\frac{4}{9}=\frac{2}{3}\cdot \frac{2}{3}={\left(\frac{2}{3}\right)}^2$

${\left(\frac{2}{3}\right)}^3=\frac{2}{3}\cdot \frac{2}{3}\cdot \frac{2}{3}=\frac{4}{9}\cdot \frac{2}{3}=\frac{8}{27}$

 

 

$\frac{1}{8}=\frac{1}{2}\cdot \frac{1}{2}\cdot \frac{1}{2}={\left(\frac{1}{2}\right)}^3$

${\left(\frac{1}{2}\right)}^2=\frac{1}{2}\cdot \frac{1}{2}=\frac{1}{4}$

 

 

 

liczba dodatnia	$1\frac{3}{4}$	$\frac{2}{3}$	$\frac{1}{2}$
kwadrat tej liczby	$3\frac{1}{16}$	$\frac{4}{9}$	$\frac{1}{4}$
sześcian tej liczby	$5\frac{23}{64}$	$\frac{8}{27}$	$\frac{1}{8}$