I gimnazjum

Policzmy to razem 1

a) 7x3+□=−2x3    □=−2x3−7x3=−9x3

Rozwiązanie 1

a) 32​x+65​x−23​x=   64​x+65​x−69​x=   69​x−69​x=0     b) 81<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='1.08em' viewBox='0 0 400000 1080' preserveAspectRatio='xMinYMin slice'><path d='M95,702
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M834 80h400000v40h-400000z'/></svg>​x2y−100<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='1.08em' viewBox='0 0 400000 1080' preserveAspectRatio='xMinYMin slice'><path d='M95,702
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M834 80h400000v40h-400000z'/></svg>​x2y+49<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='1.08em' viewBox='0 0 400000 1080' preserveAspectRatio='xMinYMin slice'><path d='M95,702
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M834 80h400000v40h-400000z'/></svg>​x2y=

a) 21​xy−13x2y2​−9x2​​+8y2+9x2​​+13x2y2​=

Najpierw redukujemy wyrazy podobne:  10x2​−3​​−2x−7​​−3x2​=

2⋅k⋅m⋅m⋅4⋅k⋅k⋅m⋅(−k)⋅(−1)=

A. Nie można dodać wyrażeń, bo nie są one podobne   B.  18x2y3⋅x2y3=18x2+2y3+3=18x4y6

6xy+2x2−8x+4y+5x−6xy−2x2=

−3x2​−8y​​+10x2​−5y2+6xy+8y​​−7x2​=