Suma miar kątów w każdym trójkącie wynosi  ${180}^{\circ }$  

a) 

$\beta =\left({180}^{\circ }-{49}^{\circ }\right):2={131}^{\circ }:2={65,5}^{\circ }$  

b)

$\alpha ={180}^{\circ }-{53}^{\circ }-{36}^{\circ }={91}^{\circ }$  

c) 

$\beta ={180}^{\circ }-{125}^{\circ }={55}^{\circ }$  

$\alpha ={180}^{\circ }-{55}^{\circ }-{55}^{\circ }={70}^{\circ }$  

d)

$\gamma ={180}^{\circ }-{90}^{\circ }-{32}^{\circ }={58}^{\circ }$  

e)

$\gamma =\left({180}^{\circ }-{104}^{\circ }\right):2={76}^{\circ }:2={38}^{\circ }$  

f)

$\delta ={180}^{\circ }-{28}^{\circ }-{57}^{\circ }={95}^{\circ }$