II gimnazjum

Matematyka wokół nas 2

(x2−y2):2(x3+y3)2=2(x3+y3)2x2−y2​ (x2−y2):2(x3+y3)2=2(x3+y3)2x2−y2​ &lt;br&gt; <section class="answer"><h4 class="answer-heading">Odpowiedź:</h4> D</section>

Rozwiązanie 1

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c-10,0,-16.667,5,-20,15z M188 15 H145 v585 v600 v585 h43z'/></svg>​=(−1)⋅<svg xmlns="http://www.w3.org/2000/svg" width='0.333em' height='1.800em' viewBox='0 0 333 1800'><path d='M145 15 v585 v600 v585 c2.667,10,9.667,15,21,15
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a−b+c1​1​=34941​ a−b+c1​1​=4−498​ a=4

5x3y−2x(x2y−x)−(3x3y−2x2)=5x3y−2x3y+2x2−3x3y+2x2=

Każdą liczbę dwucyfrową o liczbie dziesiątek a i liczbie jedności b można zapisać jako 10a+b (np. 46=4⋅10+6 )

Dzielimy figurę 2 pionowymi kreskami na trójkąt prostokąt oraz trapez.    P∇​=21​⋅3x⋅(8x+4−(4x+4))=21​⋅3x⋅(8x+4−4x−4)=21​⋅3x⋅4x=21​⋅12x2=6x2

długość boku po zwiększeniu: y+20%⋅y=y+10020​y=y+102​y=y+0,2y=1,2y