$\text{I.}$

${\text{A. x}}^2-8\left(\text{x}-2\right)={\text{x}}^2-8\text{x}+16$

$\text{B.}{\left(\text{x}+4\right)}^2={\text{x}}^2+8\text{x}+16$

$\text{C.}{\left(\text{x}-4\right)}^2={\text{x}}^2-8\text{x}+16$ $\text{C.}{\left(\text{x}-4\right)}^2={\text{x}}^2-8\text{x}+16$

$\text{D.}\left(\text{x}-4\right)\left(\text{x}-4\right)={\left(\text{x}-4\right)}^2={\text{x}}^2-8\text{x}+16$

$\text{Odp.: A, C, D}$

 

$\text{II.}$

$\text{A.}{\left(\frac{1}{10}\text{x}+5\right)}^2=\frac{1}{100}{\text{x}}^2+2\cdot \frac{1}{10}\text{x}\cdot 5+25=\frac{1}{100}{\text{x}}^2+\text{x}+25$

$\text{B.}0,01\text{x}\cdot \text{x}+\text{x}+25=0,01{\text{x}}^2+\text{x}+25$

$\text{C.}\left(0,1\text{x}+5\right)\left(0,1\text{x}+5\right)={\left(0,1\text{x}+5\right)}^2=0,01{\text{x}}^2+2\cdot 0,1\cdot \text{x}\cdot 5+25=0,01{\text{x}}^2+\text{x}+25$

$\text{D.}\text{x}\left(0,01\text{x}+1\right)+25=0,01{\text{x}}^2+\text{x}+25$

$\text{Odp. A, B, C, D}$

 

$\text{III.}$

$\text{A.}\text{x}\left(3\text{x}-2\sqrt{3}\text{y}\right)+{\text{y}}^2=3{\text{x}}^2-2\sqrt{3}\text{xy}+{\text{y}}^2$

$\text{B.}{\left(\sqrt{3}\text{x}-\text{y}\right)}^2={\left(\sqrt{3}\text{x}\right)}^2-2\cdot \sqrt{3}\text{x}\cdot \text{y}+{\text{y}}^2=3{\text{x}}^2-2\sqrt{3}\text{xy}+{\text{y}}^2$

$\text{C.}{\left(3\text{x}-\text{y}\right)}^2=9{\text{x}}^2-6\text{xy}+{\text{y}}^2$

$\text{D.}\left(\sqrt{3}\text{x}-\text{y}\right)\left(\sqrt{3}\text{x}-\text{y}\right)={\left(\sqrt{3}\text{x}-\text{y}\right)}^2\text{- to samo co w podpunkcie B}$

$\text{Odp.: A, B, D}$