$25\frac{1}{2}-\left(2\cdot \frac{3}{4}+5\cdot \frac{1}{2}+3\cdot 1\frac{4}{5}\right)=25\frac{1}{2}-\left(\frac{3}{4}+\frac{5}{2}+3\cdot \frac{9}{5}\right)=25\frac{1}{2}-\left(\frac{8}{2}+\frac{27}{5}\right)=25\frac{1}{2}-\left(\frac{40}{10}+\frac{54}{10}\right)=25\frac{1}{2}-\frac{94}{10}=25\frac{1}{2}-9\frac{4}{5}=25\frac{5}{10}-9\frac{4}{10}=16\frac{1}{10}$

 

Odpowiedź:

Zostało jeszcze $16\frac{1}{10}$ metra tasiemki.