$\text{Dane:}$

$\text{m}=0,1\text{kg}$

$\text{h}=14\text{m}$

$\text{g}=10\frac{\text{N}}{\text{kg}}$

$\text{wysokosˊcˊ 14 m}$

$\Delta {\text{E}}_{\text{p}}=\text{mgh}$

$\Delta {\text{E}}_{\text{p}}=0,1\sout{\text{kg}}\cdot 10\frac{\text{N}}{\sout{\text{kg}}}\cdot 14\text{m}$

$\Delta {\text{E}}_{\text{p}}=14\text{J}$

$\Delta {\text{E}}_{\text{k}}=0\text{J}$

Teraz możemy obliczyć energię mechaniczą układu z zasady zachowania energii:

${\text{E}}_{\text{m}}=\Delta {\text{E}}_{\text{p}}+\Delta {\text{E}}_{\text{k}}$

${\text{E}}_{\text{m}}=14\text{J}+0\text{J}$

${\text{E}}_{\text{m}}=14\text{J}$

 

$\text{wysokosˊcˊ 10 m}$

$\Delta {\text{E}}_{\text{p}}=\text{mgh}$

$\Delta {\text{E}}_{\text{p}}=0,1\sout{\text{kg}}\cdot 10\frac{\text{N}}{\sout{\text{kg}}}\cdot 10\text{m}$

$\Delta {\text{E}}_{\text{p}}=10\text{J}$

Z zasady zachowania energii mamy:

${\text{E}}_{\text{m}}=\Delta {\text{E}}_{\text{p}}+\Delta {\text{E}}_{\text{k}}$

Zatem:

$\Delta {\text{E}}_{\text{k}}={\text{E}}_{\text{m}}-\Delta {\text{E}}_{\text{p}}$

$\Delta {\text{E}}_{\text{k}}=14\text{J}-10\text{J}$

$\Delta {\text{E}}_{\text{k}}=4\text{J}$

 

$\text{wysokosˊcˊ 5 m}$

$\Delta {\text{E}}_{\text{p}}=\text{mgh}$

$\Delta {\text{E}}_{\text{p}}=0,1\sout{\text{kg}}\cdot 10\frac{\text{N}}{\sout{\text{kg}}}\cdot 5\text{m}$

$\Delta {\text{E}}_{\text{p}}=5\text{J}$

$\Delta {\text{E}}_{\text{k}}={\text{E}}_{\text{m}}-\Delta {\text{E}}_{\text{p}}$

$\Delta {\text{E}}_{\text{k}}=14\text{J}-5\text{J}$

$\Delta {\text{E}}_{\text{k}}=9\text{J}$

 

$\text{wysokosˊcˊ 0 m}$

$\Delta {\text{E}}_{\text{p}}=\text{mgh}$

$\Delta {\text{E}}_{\text{p}}=0,1\sout{\text{kg}}\cdot 10\frac{\text{N}}{\sout{\text{kg}}}\cdot 0\text{m}$

$\Delta {\text{E}}_{\text{p}}=0\text{J}$

$\Delta {\text{E}}_{\text{k}}={\text{E}}_{\text{m}}-\Delta {\text{E}}_{\text{p}}$

$\Delta {\text{E}}_{\text{k}}=14\text{J}-0\text{J}$

$\Delta {\text{E}}_{\text{k}}=14\text{J}$

h [m]	Ep [J]	Ek [J]
14	14	0
10	10	4
5	5	9
0	0	14