II liceum

I technikum

II technikum

To jest chemia. Zbiór zadań zakres rozszerzony. Reforma 2019

Chemia

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Chemia 2. Karty pracy zakres podstawowy. Reforma 2019

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Chemia 2 Witowski. NOWA EDYCJA 2021. Zbiór zadań wraz z odpowiedziami 2002-2021. Reforma 2019

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Chemia 4 Witowski. NOWA EDYCJA 2021. Zbiór zadań wraz z odpowiedziami 2002-2021. Reforma 2019

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Dane: <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/fcb2cc70b52763b63c154be2e331ae362a8d4f21c7a510cdebcb83e963ce451e_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/fcb2cc70b52763b63c154be2e331ae362a8d4f21c7a510cdebcb83e963ce451e_big.svg" type="image/svg+xml"></object> &nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/127bdecf65db58a9363d19fae1822c34c7b76cdc26684ec82da8af871a438607_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/127bdecf65db58a9363d19fae1822c34c7b76cdc26684ec82da8af871a438607_big.svg" type="image/svg+xml"></object> &nbsp; Szukane: <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/5561231d2a665187476e9ba1e00d462851095f83f03d9f991517a7f6f8e1fed7_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/5561231d2a665187476e9ba1e00d462851095f83f03d9f991517a7f6f8e1fed7_big.svg" type="image/svg+xml"></object> &nbsp; Rozwiązanie: Zapisujemy równanie reakcji chemicznej:

Dane:&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/f55539e20b296a5a0139b28e1dbb0dbbecbdc129bfcf23f1850687ba7988954f_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/f55539e20b296a5a0139b28e1dbb0dbbecbdc129bfcf23f1850687ba7988954f_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/3b92171f9da30ef74542bcd058a12f6e28d5e5f375e0fd9b89c2c015fa7f4925_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/3b92171f9da30ef74542bcd058a12f6e28d5e5f375e0fd9b89c2c015fa7f4925_big.svg" type="image/svg+xml"></object> &nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/127bdecf65db58a9363d19fae1822c34c7b76cdc26684ec82da8af871a438607_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/127bdecf65db58a9363d19fae1822c34c7b76cdc26684ec82da8af871a438607_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp; Szukane:&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/54f06b891d992e24dacbf071016d5aa913679f7b82c4b72fa6aedf73996a1050_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/54f06b891d992e24dacbf071016d5aa913679f7b82c4b72fa6aedf73996a1050_big.svg" type="image/svg+xml"></object> &nbsp; Rozwiązanie:&nbsp; Masy molowe reagentów:&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/72e66fd84fca4472fb57dbf3a4cae64b94b92bd98b796fe9b13c27bf5663976c_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/72e66fd84fca4472fb57dbf3a4cae64b94b92bd98b796fe9b13c27bf5663976c_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/eeba4ebd5ab38d6b218f7a2273bab7400090d10ba25e8a60344e4edeb2edb3b6_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/eeba4ebd5ab38d6b218f7a2273bab7400090d10ba25e8a60344e4edeb2edb3b6_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp;

Dane:&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/b7573e50fc18324ccff1d569bbaf799692c2ee2eba69f35cdd06b2cd31455be1_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/b7573e50fc18324ccff1d569bbaf799692c2ee2eba69f35cdd06b2cd31455be1_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/2c4815fc48f60a9fbd90895dc64daba2cdbd4094bea19505cdb6f647a351b7a4_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/2c4815fc48f60a9fbd90895dc64daba2cdbd4094bea19505cdb6f647a351b7a4_big.svg" type="image/svg+xml"></object> &nbsp; &nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/c495680d4bf41ba79e809f6aff0c44081ccca0c339acd857d8dba964f3030177_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/c495680d4bf41ba79e809f6aff0c44081ccca0c339acd857d8dba964f3030177_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/48f426fa9b75b6ff21f4e9c979cc6881f09eb4c45bc3eb6cc303bfd5965620f4_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/48f426fa9b75b6ff21f4e9c979cc6881f09eb4c45bc3eb6cc303bfd5965620f4_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/6dbe2cebda5aaf6bb8736ec3771f1b09fbf3a867def9bdc9eb294022b77ce21b_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/6dbe2cebda5aaf6bb8736ec3771f1b09fbf3a867def9bdc9eb294022b77ce21b_big.svg" type="image/svg+xml"></object> &nbsp; &nbsp;&nbsp; Szukane:&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/b52d0b80de24db45af7ce2cb04543c025535165a83784f92cb1c654e6e83fcdd_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/b52d0b80de24db45af7ce2cb04543c025535165a83784f92cb1c654e6e83fcdd_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp; Rozwiązanie:&nbsp; Znając masę roztworu węglanu potasu oraz jego stężenie, obliczamy masę substancji rozpuszczonej, czyli "czystego" węglanu potasu, korzystamy z poniższego wzoru:&nbsp;

Dane:&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/81f2d0c3c0f52d2fe9ce700da2e9d2b42d950e7b39c8c1b602e21fb15f3632e0_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/81f2d0c3c0f52d2fe9ce700da2e9d2b42d950e7b39c8c1b602e21fb15f3632e0_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/07b9644d67065c02578b1b0ccd1cb10bd739c2a2e71a32fa9528f5b1cb361cbe_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/07b9644d67065c02578b1b0ccd1cb10bd739c2a2e71a32fa9528f5b1cb361cbe_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/0c0b67debf670e2f9e7b7b45ef0dcb4477bb536c2d5f0fef9710174507796cf4_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/0c0b67debf670e2f9e7b7b45ef0dcb4477bb536c2d5f0fef9710174507796cf4_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp; Szukane:&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/099cca5764c6dfff0cb6bfad628fabd45c2f930af6d748fd148dba121cdff5ee_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/099cca5764c6dfff0cb6bfad628fabd45c2f930af6d748fd148dba121cdff5ee_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp; Rozwiązanie:&nbsp; Obliczamy masy molowe substratów:&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/0d29e935a6934d99530a906b3542dd8abc2b362cc0b78fdf66291a62aa151914_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/0d29e935a6934d99530a906b3542dd8abc2b362cc0b78fdf66291a62aa151914_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/72e66fd84fca4472fb57dbf3a4cae64b94b92bd98b796fe9b13c27bf5663976c_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/72e66fd84fca4472fb57dbf3a4cae64b94b92bd98b796fe9b13c27bf5663976c_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/03bd2b36e0c73831f522b63c8c54e0e249bb31abc7f081e7444e38c7ef73be05_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/03bd2b36e0c73831f522b63c8c54e0e249bb31abc7f081e7444e38c7ef73be05_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp; Zapisujemy równanie reakcji chemicznej:&nbsp;

Dane:&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/02d868c43735833f78dae19a2125afd227894f1f2ccea4d88c6d48e9c3d199c3_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/02d868c43735833f78dae19a2125afd227894f1f2ccea4d88c6d48e9c3d199c3_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/a5a23fbf271426dfd4fde9d2cd1c864626026939d53d794f51d348367164a06a_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/a5a23fbf271426dfd4fde9d2cd1c864626026939d53d794f51d348367164a06a_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp; Szukane:&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/459c0abdb74c500cc392037f7ea3ce85cf0fd976c4dcf8b61fbfd348dd1f5cd6_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/459c0abdb74c500cc392037f7ea3ce85cf0fd976c4dcf8b61fbfd348dd1f5cd6_big.svg" type="image/svg+xml"></object> &nbsp; &nbsp; Rozwiązanie:&nbsp; Obliczamy masy molowe reagentów:&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/2c631733ffb341ab4e11aa74e7d8c4c08acab3c4d95fa571e9324c16725456a3_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/2c631733ffb341ab4e11aa74e7d8c4c08acab3c4d95fa571e9324c16725456a3_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/84865019addaca426e9751152a3cfdca150fb555c41a0debc1e633f511bd55c0_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/84865019addaca426e9751152a3cfdca150fb555c41a0debc1e633f511bd55c0_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp;

Dane:&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/38c27832c26123246fca0ab0826f2db0f5810b3b491a216ce54fbac3277848aa_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/38c27832c26123246fca0ab0826f2db0f5810b3b491a216ce54fbac3277848aa_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/0d34a8c84ddc05855d7f6dbc18f9d8ea364db67a13a671ed12cce26e8e9106f4_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/0d34a8c84ddc05855d7f6dbc18f9d8ea364db67a13a671ed12cce26e8e9106f4_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/70abffa8f1629f01026055679a88f707aa2a369601dfcf42cfa5cc2473e553f5_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/70abffa8f1629f01026055679a88f707aa2a369601dfcf42cfa5cc2473e553f5_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/79a94cc4988d81395b35f9109431a98c9720d0389344c37629a6984741668fcf_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/79a94cc4988d81395b35f9109431a98c9720d0389344c37629a6984741668fcf_big.svg" type="image/svg+xml"></object> &nbsp; &nbsp;&nbsp; Szukane:&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/580d054fb8e8689f89fae583ada55934339386bbaa564e869e1000d8ac608c78_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/580d054fb8e8689f89fae583ada55934339386bbaa564e869e1000d8ac608c78_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp;&nbsp; Rozwiązanie:&nbsp; Znając objętości oraz gęstości substratów obliczamy ich masy, korzystamy ze wzoru na gęstość:&nbsp; <object class="math small" data="https://odrabiamy.pl/api/v3/math_formulas/5c4e970dbd822a27129868ee6aae36138c2b0b11d8c56a3a71e135104cf03d03_small.svg" type="image/svg+xml"></object><object class="math big" data="https://odrabiamy.pl/api/v3/math_formulas/5c4e970dbd822a27129868ee6aae36138c2b0b11d8c56a3a71e135104cf03d03_big.svg" type="image/svg+xml"></object> &nbsp;&nbsp; &nbsp; Masa kwasu octowego i etanolu wynoszą odpowiednio:&nbsp;

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