$a)$

$3^3=3\cdot 3\cdot 3=27$

$0^{250}=0$

${11}^2=121$

${\left(\frac{1}{2}\right)}^4=\frac{1}{16}$

${\left(-2\frac{1}{4}\right)}^2={\left(-\frac{9}{4}\right)}^2=\frac{{\left(-9\right)}^2}{4^2}=\frac{81}{16}=5\frac{1}{16}$ ${\left(-2\frac{1}{4}\right)}^2={\left(-\frac{9}{4}\right)}^2=\frac{{\left(-9\right)}^2}{4^2}=\frac{81}{16}=5\frac{1}{16}$

${\left(-0,6\right)}^3=\left(-0,6\right)\cdot \left(-0,6\right)\cdot \left(-0,6\right)=\left(-0,216\right)$

 

$b)$

${\left(-2\right)}^3=\left(-8\right)$

${\left(-0,2\right)}^3=\left(-0,2\right)\cdot \left(-0,2\right)\cdot \left(-0,2\right)=\left(-0,008\right)$

${12}^2=144$

${\left(-\frac{1}{3}\right)}^2=\frac{1}{9}$

${\left(-1\frac{1}{2}\right)}^3={\left(-\frac{3}{2}\right)}^3=\left(-\frac{27}{8}\right)=\left(-3\frac{3}{8}\right)$

${\left(0,2\right)}^5=0,2\cdot 0,2\cdot 0,2\cdot 0,2\cdot 0,2=0,00032$

 

 

$c)$

${\left(0,3\right)}^3=0,09$

${\left(-0,1\right)}^6)=0,000001$

${13}^2=169$

${\left(\frac{3}{4}\right)}^3=\frac{27}{64}$

${\left(3\frac{1}{3}\right)}^0=1$

${\left(1,3\right)}^2=1,69$