a) ${10}^{-4}\cdot 2,2\cdot {10}^{12}=2,2\cdot {10}^{8}kg=2,2\cdot {10}^{5}t$

b) $\frac{0,15}{{10}^{-7}}=0,15\cdot {10}^7=15\cdot {10}^5$ razy

c) $d=\frac{m}{V}\Rightarrow m=dV$ czyli   $m=5,5\cdot {10}^3\cdot 1,1\cdot {10}^{21}=6,05\cdot {10}^{24}kg$