II gimnazjum

Matematyka z plusem 2

a) (x+2)(y+1)=x⋅y+x⋅1+2⋅y+2⋅1=   xy+x+2y+2    b) (2a+1)(3−b)=   2a⋅3+2a⋅(−b)+1⋅3+1⋅(−b)=

a) (x+1)(x+2)=x⋅x+x⋅2+1⋅x+1⋅2=x2+2x+x+2=x2+3x+2 b) (3a+4)(a−5)=3a⋅a+3a⋅(−5)+4⋅a+4⋅(−5)=3a2−15a+4a−20=3a2−11a−20

a) P=(x+5)(x−2)=x⋅x+x⋅(−2)+5⋅x+5⋅(−2)=x2−2x+5x−10=x2+3x−10

a) (3<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='1.08em' viewBox='0 0 400000 1080' preserveAspectRatio='xMinYMin slice'><path d='M95,702
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M834 80h400000v40h-400000z'/></svg>​⋅23<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='1.08em' viewBox='0 0 400000 1080' preserveAspectRatio='xMinYMin slice'><path d='M95,702
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H400000v40H845.2724
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M834 80h400000v40h-400000z'/></svg>​+3<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='1.08em' viewBox='0 0 400000 1080' preserveAspectRatio='xMinYMin slice'><path d='M95,702
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c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M834 80h400000v40h-400000z'/></svg>​⋅(−2)+23<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='1.08em' viewBox='0 0 400000 1080' preserveAspectRatio='xMinYMin slice'><path d='M95,702
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M834 80h400000v40h-400000z'/></svg>​−2=2⋅3−23<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='1.08em' viewBox='0 0 400000 1080' preserveAspectRatio='xMinYMin slice'><path d='M95,702
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H400000v40H845.2724
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c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M834 80h400000v40h-400000z'/></svg>​+23<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='1.08em' viewBox='0 0 400000 1080' preserveAspectRatio='xMinYMin slice'><path d='M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
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M834 80h400000v40h-400000z'/></svg>​−2=6−2=4

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