$a)2^{-3}={\left(\frac{1}{2}\right)}^3=\frac{1}{8}\ne 8$  

$b){\left(\frac{1}{2}\right)}^{-2}={\left(\frac{2}{1}\right)}^2=2^2=4\ne 2$  

$c){\left(-3\right)}^{-2}={\left(-\frac{1}{3}\right)}^2=\frac{1}{9}$  

$d){\left(-1\right)}^{-1}=-1\ne 1$  

$e){\left(2\frac{1}{3}\right)}^{-1}={\left(\frac{7}{3}\right)}^{-1}=\frac{3}{7}\ne 3\frac{1}{2}$   

$f){\left(-1\right)}^{-4}={\left(-1\right)}^4=1\ne -1$  

$g){\left(1\frac{3}{4}\right)}^{-1}={\left(\frac{7}{4}\right)}^{-1}={\left(\frac{4}{7}\right)}^1=\frac{4}{7}\ne 1\frac{4}{3}$  

$h){\left(0,2\right)}^{-1}={\left(\frac{2}{10}\right)}^{-1}=\frac{10}{2}=5$  

Odpowiedź:

a, b, d, e, f, g.