Wykonajmy obliczenia.

B.

$\frac{6}{16}+\frac{9}{16}=\frac{15}{16}$

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C.

$\frac{7}{8}-\frac{1}{4}=\frac{7}{8}-\frac{2}{8}=\frac{5}{8}$

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I.

$\underline{3\frac{1}{3}+\frac{7}{9}}+2=\underline{3\frac{3}{9}+\frac{7}{9}}+2=3\frac{10}{9}+2=$

$=4\frac{1}{9}+2=6\frac{1}{9}$

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B.

$\frac{7}{9}+\frac{16}{27}=\frac{21}{27}+\frac{16}{27}=\frac{37}{27}=1\frac{10}{27}$

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A.

$\frac{7}{15}-\frac{4}{45}=\frac{21}{45}-\frac{4}{45}=\frac{17}{45}$

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Z.

$\underline{8-2\frac{1}{5}}+1\frac{1}{45}=\underline{8-2-\frac{1}{5}}+1\frac{1}{45}=$

$=\underline{6-\frac{1}{5}}+1\frac{1}{45}=5\frac{4}{5}+1\frac{1}{45}=$

$=5\frac{36}{45}+1\frac{1}{45}=6\frac{37}{45}$

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C.

$\frac{7}{12}+1\frac{1}{4}=\frac{7}{12}+1\frac{3}{12}=1\frac{10}{12}=1\frac{5}{6}$

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Y.

$1\frac{2}{17}-\frac{15}{34}=1\frac{4}{34}-\frac{15}{34}=\frac{38}{34}-\frac{15}{34}=\frac{23}{34}$

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Y.

$8\frac{1}{6}-\left(2\frac{3}{8}+\frac{1}{4}\right)=8\frac{1}{6}-\left(2\frac{3}{8}+\frac{2}{8}\right)=$

$=8\frac{1}{6}-2\frac{5}{8}=8\frac{4}{24}-2\frac{15}{24}=$

$=7\frac{28}{24}-2\frac{15}{24}=5\frac{13}{24}$

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L.

$2\frac{3}{4}+3\frac{3}{20}=2\frac{15}{20}+3\frac{3}{20}=5\frac{18}{20}=5\frac{9}{10}$

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Ń

$6\frac{1}{13}-2\frac{7}{39}=6\frac{3}{39}-2\frac{7}{39}=$

$=5\frac{42}{39}-2\frac{7}{39}=3\frac{35}{39}$

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O.

$\left(2\frac{1}{3}-\frac{5}{6}\right)+3\frac{10}{12}=\left(2\frac{2}{6}-\frac{5}{6}\right)+3\frac{10}{12}=$

$=\left(1\frac{8}{6}-\frac{5}{6}\right)+3\frac{10}{12}=1\frac{3}{6}+3\frac{5}{6}=$

$=4\frac{8}{6}=4\frac{4}{3}=5\frac{1}{3}$

Układamy hasło:

$\frac{15}{16}$	$\frac{17}{45}$	$1\frac{10}{27}$	$6\frac{1}{9}$	$5\frac{9}{10}$	$5\frac{1}{3}$	$3\frac{35}{39}$	$1\frac{5}{6}$	$6\frac{37}{45}$	$\frac{23}{34}$	$\frac{5}{8}$	$5\frac{13}{24}$
B	A	B	I	L	O	Ń	C	Z	Y	C	Y