$\text{a)}{4}^{-2}=\frac{1}{4^2}=\frac{1}{16}$

$\text{b)}{4}^{-3}=\frac{1}{4^3}=\frac{1}{64}$

$\text{c)}{\left(-3\right)}^{-2}=\frac{1}{{\left(-3\right)}^2}=\frac{1}{9}$

$\text{d)}{\left(-3\right)}^{-3}=\frac{1}{{\left(-3\right)}^3}=\frac{1}{-27}=-\frac{1}{27}$

$\text{e)}{\left(\frac{1}{2}\right)}^{-2}=\frac{1}{{\left(\frac{1}{2}\right)}^2}=\frac{1}{\frac{1}{4}}=4$

$\text{f)}{\left(\frac{1}{2}\right)}^{-5}=\frac{1}{{\left(\frac{1}{2}\right)}^5}=\frac{1}{\frac{1}{32}}=32$

$\text{g)}{\left(\frac{2}{3}\right)}^{-2}=\frac{1}{{\left(\frac{2}{3}\right)}^2}=\frac{1}{\frac{4}{9}}=\frac{9}{4}=2\frac{1}{4}$

$\text{h)}{\left(-\frac{2}{3}\right)}^{-4}=\frac{1}{{\left(-\frac{2}{3}\right)}^4}=\frac{1}{\frac{16}{81}}=\frac{81}{16}=5\frac{1}{16}$

$\text{i)}{0,2}^{-2}={\left(\frac{1}{5}\right)}^{-2}=\frac{1}{{\left(\frac{1}{5}\right)}^2}=\frac{1}{\frac{1}{25}}=25$

$\text{j)}{\left(-0,2\right)}^{-3}={\left(-\frac{1}{5}\right)}^{-3}=\frac{1}{{\left(-\frac{1}{5}\right)}^3}=\frac{1}{-\frac{1}{125}}=-125$