Zapiszmy podane wielkości w postaci wyrażeń dwumianowanych.

a)

$4,21\text{m}=4\text{m}+\underset{21\text{ cm}}{\underbrace{0,21\text{m}}}=4\text{m}21\text{cm}$

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$10,05\text{m}=10\text{m}+\underset{5\text{ cm}}{\underbrace{0,05\text{m}}}=10\text{m}5\text{cm}$

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$1,4\text{m}=1\text{m}+\underset{40\text{ cm}}{\underbrace{0,40\text{m}}}=1\text{m}40\text{cm}$

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b)

$21,067\text{t}=21\text{t}+\underset{67\text{ kg}}{\underbrace{0,067\text{t}}}=21\text{t}67\text{kg}$

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$10,5\text{t}=10\text{t}+\underset{500\text{ kg}}{\underbrace{0,500\text{t}}}=10\text{t}500\text{kg}$

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$6,07\text{t}=6\text{t}+\underset{70\text{ kg}}{\underbrace{0,070\text{t}}}=6\text{t}70\text{kg}$

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c)

$1,106\text{km}=1\text{km}+\underset{106^{}\text{ m}}{\underbrace{0,106\text{km}}}=1\text{km}106\text{m}$

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$7,25\text{km}=7\text{km}+\underset{250^{}\text{ m}}{\underbrace{0,250\text{km}}}=7\text{km}250\text{m}$

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$8,6\text{km}=8\text{km}+\underset{600\text{ m}}{\underbrace{0,600\text{km}}}=8\text{km}600\text{m}$

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d)

$1,42\text{kg}=1\text{kg}+\underset{42^{}\text{ dag}}{\underbrace{0,42\text{kg}}}=1\text{kg}42\text{dag}$

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$6,007\text{kg}=6\text{kg}+\underset{7^{}\text{ g}}{\underbrace{0,007\text{kg}}}=6\text{kg}7\text{g}$

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$5,3\text{kg}=5\text{kg}+\underset{30^{}\text{ dag}}{\underbrace{0,30\text{kg}}}=5\text{kg}30\text{dag}$