a)

Wiemy, że:

$1\text{dag}=\boxed{10}\text{g}$

Zatem:

$1\text{g}=\boxed{0,1}\text{dag}$ (bo $1\text{g}=\frac{1}{10}\text{dag}$)

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Uzupełniamy:

$7\text{g}=\boxed{0,7}\text{dag}$ (bo $7\text{g}=\frac{7}{10}\text{dag}$)

$16\text{dag}8\text{g}=\boxed{16,8}\text{dag}$ (bo $8\text{g}=\frac{8}{10}\text{dag}$)

$45\text{g}=\boxed{4,5}\text{dag}$ (bo $45\text{g}=\frac{45}{10}\text{dag}=4\frac{5}{10}\text{dag}$)

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b)

Wiemy, że:

$1\text{kg}=\boxed{100}\text{dag}$

Zatem:

$1\text{dag}=\boxed{0,01}\text{kg}$ (bo $1\text{dag}=\frac{1}{100}\text{kg}$)

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Uzupełniamy:

$34\text{dag}=\boxed{0,34}\text{kg}$ (bo $34\text{dag}=\frac{34}{100}\text{kg}$)

$6\text{kg}45\text{dag}=\boxed{6,45}\text{kg}$ (bo $45\text{dag}=\frac{45}{100}\text{kg}$)

$207\text{dag}=\boxed{2,07}\text{kg}$ (bo $207\text{dag}=\frac{207}{100}\text{kg}=2\frac{7}{100}\text{kg}$)

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c)

Wiemy, że:

$1\text{t}=\boxed{1000}\text{kg}$

Zatem:

$1\text{kg}=\boxed{0,001}\text{t}$ (bo $1\text{kg}=\frac{1}{1000}\text{t}$)

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Uzupełniamy:

$164\text{kg}=\boxed{0,164}\text{t}$ (bo $164\text{kg}=\frac{164}{1000}\text{t}$)

$4\text{t}8\text{kg}=\boxed{4,008}\text{t}$ (bo $8\text{kg}=\frac{8}{1000}\text{t}$)

$2035\text{kg}=\boxed{2,035}\text{t}$ (bo $2035\text{kg}=\frac{2035}{1000}\text{t}=2\frac{35}{1000}\text{t}$)

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d)

Wiemy, że:

$1\text{kg}=\boxed{1000}\text{g}$

Zatem:

$1\text{g}=\boxed{0,001}\text{kg}$ (bo $1\text{g}=\frac{1}{1000}\text{kg}$)

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Uzupełniamy:

$301\text{g}=\boxed{0,301}\text{kg}$ (bo $301\text{g}=\frac{301}{1000}\text{kg}$)

$1\text{kg}52\text{g}=\boxed{1,052}\text{kg}$ (bo $52\text{g}=\frac{52}{1000}\text{kg}$)

$7009\text{g}=\boxed{7,009}\text{kg}$ (bo $7009\text{g}=\frac{7009}{1000}\text{kg}=7\frac{9}{1000}\text{kg}$)