$R\left(A\right)=\log \frac{A}{{10}^{-4}}$  

${10}^{R\left(A\right)}=\frac{A}{{10}^{-4}}$  

$A={10}^{R\left(A\right)-4}$

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$A_1={10}^{1-4}=0,001\text{cm}=0,00001\text{m}$  

$A_2={10}^{2-4}=0,01\text{cm}=0,0001\text{m}$  

$A_3={10}^{3-4}=0,1\text{cm}=0,001\text{m}$  

$A_4={10}^{4-4}=1\text{cm}=0,01\text{m}$  

$A_5={10}^{5-4}=10\text{cm}=0,1\text{m}$  

$A_6={10}^{6-4}=100\text{cm}=1\text{m}$  

$A_7={10}^{7-4}=1000\text{cm}=10\text{m}$  

$A_8={10}^{8-4}=10000\text{cm}=100\text{m}$  

$A_9={10}^{9-4}=100000\text{cm}=1000\text{m}$  

$A_{10}={10}^{10-4}=1000000\text{cm}=10000\text{m}$  

Tabelka

R	$1$	$2$	$3$	$4$	$5$	$6$	$7$	$8$	$9$	$10$
A [m]	$0,00001$	$0,0001$	$0,001$	$0,01$	$0,1$	$1$	$10$	$100$	$1000$	$10000$

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a) Zauważmy, że

$R=5,5\to A={10}^{1,5}\text{cm}$  

$R=3,5\to A={10}^{-0,5}\text{cm}$  

Drugie jest 100 razy silniejsze. Prawda.

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b) Mamy

$R=9,5\to {10}^{5,5}\text{cm}={10}^{3,5}\text{m}>1\text{km}$  

Prawda.