Wyniki doświadczenia są zbiorem uporządkowanych par postaci (a, b), gdzie a oznacza wynik pierwszego rzutu, a b - wynik drugiego rzutu. 

$\Omega =\left\{\left(1,1\right),\left(1,2\right),\left(1,3\right),\left(1,4\right),\left(1,5\right),\left(1,6\right),\left(2,1\right),\left(2,2\right),\left(2,3\right),\left(2,4\right),\left(2,5\right),\left(2,6\right),\left(3,1\right),\left(3,2\right),\left(3,3\right),\left(3,4\right),\left(3,5\right),\left(3,6\right),\left(4,1\right),\left(4,2\right),\left(4,3\right),\left(4,4\right),\left(4,5\right),\left(4,6\right),\left(5,1\right),\left(5,2\right),\left(5,3\right),\left(5,4\right),\left(5,5\right),\left(5,6\right),\left(6,1\right),\left(6,2\right),\left(6,3\right),\left(6,4\right),\left(6,5\right),\left(6,6\right)\right\}$  

$\left|\Omega \right|=36$  

---

Wypiszmy doświadczenia sprzyjające danym zdarzeniom:

$A=\left\{\left(1,2\right),\left(1,4\right),\left(1,6\right),\left(2,1\right),\left(2,3\right),\left(2,5\right),\left(3,2\right),\left(3,4\right),\left(3,6\right),\left(4,1\right),\left(4,3\right),\left(4,5\right),\left(5,2\right),\left(5,4\right),\left(5,6\right),\left(6,1\right),\left(6,3\right),\left(6,5\right)\right\}$  

$\left|A\right|=18$  

$\left|A{}^{\prime }\right|=\left|\Omega \right|-\left|A\right|=36-18=18$  

---

$B=\left\{\left(1,1\right),\left(1,2\right),\left(1,3\right),\left(1,4\right),\left(1,5\right),\left(1,6\right),\left(2,1\right),\left(2,2\right),\left(2,3\right),\left(2,4\right),\left(2,5\right),\left(2,6\right),\left(3,1\right),\left(3,2\right),\left(3,3\right),\left(3,4\right),\left(4,1\right),\left(4,2\right),\left(4,3\right),\left(5,1\right),\left(5,2\right),\left(6,1\right),\left(6,2\right)\right\}$  

$\left|B\right|=23$  

$\left|B{}^{\prime }\right|=\left|\Omega \right|-\left|B\right|=36-23=13$  

---

$C=\left\{\left(5,5\right),\left(5,6\right),\left(6,5\right),\left(6,6\right)\right\}$  

$\left|C\right|=4$  

$\left|C{}^{\prime }\right|=\left|\Omega \right|-\left|C\right|=36-4=32$  

---

Żadna odpowiedź nie jest prawidłowa.