Sprowadźmy wyrażenie podane w zadaniu do potęgi liczby 2:

$\frac{\sqrt[3]{16}\cdot 2^5:{\left(4^{-\frac{1}{3}}\right)}^5}{{\left(\frac{1}{2}\right)}^5:8^{-\frac{2}{3}}\cdot 32}=\frac{\sqrt[3]{2^4}\cdot 2^5:{\left({\left(2^2\right)}^{-\frac{1}{3}}\right)}^5}{2^{-5}:{\left(2^{{\cancel{3}}^1}\right)}^{-\frac{2}{{\cancel{3}}_1}}\cdot 2^5}=$  

$=\frac{2^{\frac{4}{3}}\cdot 2^5:2^{-\frac{10}{3}}}{2^{-5}:2^{-2}\cdot 2^5}=\frac{2^{\frac{4}{3}+5-\left(-\frac{10}{3}\right)}}{2^{-5-\left(-2\right)+5}}=$  

$=\frac{2^{\frac{4}{3}+5+\frac{10}{3}}}{2^2}=\frac{2^{5\frac{14}{3}}}{2^2}=\frac{2^{9\frac{2}{3}}}{2^2}=2^{9\frac{2}{3}-2}=$  

$=2^{7\frac{2}{3}}=2^{7+\frac{2}{3}}=2^7\cdot 2^{\frac{2}{3}}=128\sqrt[3]{2^2}=128\sqrt[3]{4}$  

 

Odp. B.