Przekształć potęgę na...- Zadanie 4: Matematyka z plusem 1. Ćwiczenia podstawowe

Rozwiązanie

$a) (\frac{7}{8})^{- \frac{2}{3}} = ((\frac{7}{8})^{- 1})^{\frac{2}{3}} = (\frac{8}{7})^{\frac{2}{3}} = 3 (\frac{8}{7})^{2}$

$(\frac{7}{8})^{- \frac{2}{3}} = ((\frac{7}{8})^{\frac{2}{3}})^{- 1} = \frac{1}{3 ( \frac{7}{8} ) ^{2}} = \frac{1}{\frac{3 7 ^{2}}{3 8 ^{2}}} = 3 (\frac{8}{7})^{2}$

$b) (\frac{6}{5})^{- \frac{7}{8}} = ((\frac{6}{5})^{- 1})^{\frac{7}{8}} = (\frac{5}{6})^{\frac{7}{8}} = 8 (\frac{5}{6})^{7}$

$(\frac{6}{5})^{- \frac{7}{8}} = ((\frac{6}{5})^{\frac{7}{8}})^{- 1} = \frac{1}{8 ( \frac{6}{5} ) ^{7}} = \frac{1}{\frac{8 6 ^{7}}{8 5 ^{7}}} = 8 (\frac{5}{6})^{7}$