Przypomnijmy, że:

$\left|a\right|=\{\begin{array}{l}a\text{,}\text{gdy}a\ge 0\\ -a\text{,}\text{gdy}a<0\end{array}$  

$\text{a)}\left|-1\frac{1}{3}\right|=1\frac{1}{3}$     

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$\text{b)}\left|5,7\right|=5,7$  

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$\text{c)}\left|6-9\right|=\left|-3\right|=3$  

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$\text{d)}\left|-8\right|-\left|-5\right|=8-5=3$  

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$\text{e)}\left|-6\cdot \frac{1}{3}+\frac{2}{3}\right|=\left|-2+\frac{2}{3}\right|=\left|-1\frac{1}{3}\right|=1\frac{1}{3}$  

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$\text{f)}\left|-100\cdot 83+17\cdot \left(-100\right)\right|=\left|-8300-1700\right|=\left|-10000\right|=10000$  

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$\text{g)}\text{|}\stackrel{-}{1-\sqrt{3}}\text{|}=\sqrt{3}-1$  

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$\text{h)}\text{|}\stackrel{+}{\sqrt{3}-\sqrt{2}}\text{|}=\sqrt{3}-\sqrt{2}$  

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$\text{i)}\text{|}\stackrel{-}{\sqrt[3]{5}-\sqrt{3}}\text{|}=\sqrt{3}-\sqrt[3]{5}$  

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$\text{j)}\text{|}\stackrel{+}{2\pi -6,28}\text{|}=2\pi -6,28$