$\left[{\left(-2\right)}^{30}\cdot 2^{-1}\cdot {\left(-3\right)}^{-30}\right]\cdot \left[{\left(-\frac{1}{3}\right)}^{-30}\cdot {0,5}^{30}\right]=$ $2^{30}\cdot 2^{-1}\cdot {\left(-3\right)}^{-30}\cdot {\left(-3\right)}^{30}\cdot {\left(\frac{1}{2}\right)}^{30}=$

${\left(2\cdot \frac{1}{2}\right)}^{30}\cdot 2^{-1}\cdot {\left(-3\right)}^{-30+30}=1^{30}\cdot \frac{1}{2}\cdot {\left(-3\right)}^0$ $=1\cdot \frac{1}{2}\cdot 1=\frac{1}{2}=0,5$

Odp. D.