a) Znajdujemy pary boków proporcjonalnych:

$\frac{\left|AB\right|}{\left|DE\right|}=\frac{8}{12}=\frac{2}{3}$  

$\frac{\left|BC\right|}{\left|EF\right|}=\frac{10}{15}=\frac{2}{3}$  

$\frac{\left|AC\right|}{\left|DF\right|}=\frac{16}{24}=\frac{2}{3}$  

Zatem:

$\left|\sphericalangle CAB\right|=\left|\sphericalangle FDE\right|$  

$\left|\sphericalangle ABC\right|=\left|\sphericalangle DEF\right|$  

$\left|\sphericalangle BCA\right|=\left|\sphericalangle EFD\right|$  

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b) Znajdujemy pary kątów równych:

$\left|\sphericalangle CAB\right|=\left|\sphericalangle FDE\right|={20}^{\circ }$  

$\left|\sphericalangle ABC\right|=\left|\sphericalangle DEF\right|={36}^{\circ }$  

$\left|\sphericalangle BCA\right|=\left|\sphericalangle EFD\right|={124}^{\circ }$  

Zatem:

$\frac{\left|AB\right|}{\left|DE\right|}=\frac{\left|BC\right|}{\left|EF\right|}=\frac{\left|AC\right|}{\left|DF\right|}$