Wiemy, że:

$K=\left\{1,2,3,4,5\right\}$      

$L=\left\{0,1,2,3\right\}$  

$M=\left\{1,3,6\right\}$  


zatem:   

$a\text{)}\left(L\cup M\right)\text{}K=\left\{0,1,2,3,6\right\}\text{}\left\{1,2,3,4,5\right\}=\left\{0,6\right\}$   

$b\text{)}\left(M\text{}L\right)\cap K=\left(\left\{1,3,6\right\}\text{}\left\{0,1,2,3\right\}\right)\cap \left\{1,2,3,4,5\right\}=\left\{6\right\}\cap \left\{1,2,3,4,5\right\}=\varnothing$  

$c\text{)}\left(K\cap L\right)\cup \left(M\text{}L\right)=\left(\left\{1,2,3,4,5\right\}\cap \left\{0,1,2,3\right\}\right)\cup \left(\left\{1,3,6\right\}\text{}\left\{0,1,2,3\right\}\right)=\left\{1,2,3\right\}\cup \left\{6\right\}=\left\{1,2,3,6\right\}$  

$d\text{)}\left(K\cup M\right)\text{}\left(K\cap L\right)=\left(\left\{1,2,3,4,5\right\}\cup \left\{1,3,6\right\}\right)\text{}\left(\left\{1,2,3,4,5\right\}\cap \left\{0,1,2,3\right\}\right)=\left\{1,2,3,4,5,6\right\}\text{}\left\{1,2,3\right\}=\left\{4,5,6\right\}$