$\text{a)}\frac{\left(0,6+0,425-0,025\right):0,01}{\left(4\frac{5}{9}+6\frac{1}{9}\right)\cdot 6}=\frac{\left(0,6+0,4\right):0,01}{10\frac{6}{9}\cdot 6}=\frac{1:0,01}{10\frac{2}{3}\cdot 6}=\frac{100}{\frac{32}{{\sout{3}}^1}\cdot {\sout{6}}^2}=\frac{100}{64}=\frac{25}{16}$  

---

$\text{b)}\frac{1,5:0,03-\left(34,06+3,94\right)\cdot 5}{\left(4,375+6\frac{5}{8}\right)\cdot \left(-60\frac{2}{3}-9\frac{1}{3}\right)}=\frac{50-38\cdot 5}{\left(4\frac{3}{8}+6\frac{5}{8}\right)\cdot \left(-70\right)}=\frac{50-190}{11\cdot \left(-70\right)}=$  

$=\frac{-140}{11\cdot \left(-70\right)}=\frac{{\sout{140}}^2}{11\cdot {\sout{70}}^1}=\frac{2}{11}$  

---

$\text{c)}\frac{\frac{2}{5}\cdot 1\frac{7}{8}-0,75\cdot 4}{\left[0,8\cdot \left(-1,5\right)-3,3\right]\cdot \frac{4}{27}}=\frac{\frac{{\sout{2}}^1}{{\sout{5}}^1}\cdot \frac{{\sout{15}}^3}{{\sout{8}}^4}-\frac{3}{{\sout{4}}^1}\cdot {\sout{4}}^1}{\left[\frac{{\sout{4}}^2}{5}\cdot \left(-\frac{3}{{\sout{2}}^1}\right)-3\frac{3}{10}\right]\cdot \frac{4}{27}}=\frac{\frac{3}{4}-3}{\left(-\frac{6}{5}-3\frac{3}{10}\right)\cdot \frac{4}{27}}=$  

$=\frac{-2\frac{1}{4}}{\left(-\frac{12}{10}-3\frac{3}{10}\right)\cdot \frac{4}{27}}=\frac{-2\frac{1}{4}}{\left(-\frac{12}{10}-\frac{33}{10}\right)\cdot \frac{4}{27}}=\frac{-2\frac{1}{4}}{\left(-\frac{{\sout{45}}^5}{{\sout{10}}^5}\right)\cdot \frac{{\sout{4}}^2}{{\sout{27}}^3}}=\frac{-2\frac{1}{4}}{-\frac{2}{3}}=\frac{9}{4}\cdot \frac{3}{2}=\frac{27}{8}$  

---

$\text{d)}\frac{0,125\cdot 3\frac{1}{5}-\left(0,24:0,12\right)\cdot \left(-\frac{3}{5}\right)}{10:3\frac{1}{3}-{\sout{6}}^2\cdot \frac{2}{{\sout{3}}^1}+1\frac{7}{20}:5,4}=\frac{\frac{1}{{\sout{8}}^1}\cdot \frac{{\sout{16}}^2}{5}-2\cdot \left(-\frac{3}{5}\right)}{10:\frac{10}{3}-4+\frac{27}{20}:\frac{54}{10}}=\frac{\frac{2}{5}+\frac{6}{5}}{{\sout{10}}^1\cdot \frac{3}{{\sout{10}}^1}-4+\frac{{\sout{27}}^1}{{\sout{20}}^2}\cdot \frac{{\sout{10}}^1}{{\sout{54}}^2}}=$  

$=\frac{\frac{8}{5}}{3-4+\frac{1}{4}}=\frac{\frac{8}{5}}{-1+\frac{1}{4}}=\frac{\frac{8}{5}}{-\frac{3}{4}}=\frac{8}{5}\cdot \left(-\frac{4}{3}\right)=-\frac{32}{15}$