Obliczamy:

$\frac{4}{5}\cdot \frac{12}{15}=\frac{48}{75}=\frac{16}{25}$  

$\frac{{\sout{8}}^2}{{\sout{15}}^3}\cdot \frac{{\sout{5}}^1}{{\sout{36}}^9}=\frac{2}{27}$    

$\left(2\frac{1}{2}\right)\cdot \left(3\frac{1}{3}\right)=\frac{5}{{\sout{2}}^1}\cdot \frac{{\sout{10}}^5}{3}=\frac{25}{3}=8\frac{1}{3}$  

$\left(2\frac{1}{7}\right)\cdot \left(5\frac{3}{5}\right)=\frac{{\sout{15}}^3}{{\sout{7}}^1}\cdot \frac{{\sout{28}}^4}{{\sout{5}}^1}=12$  

$\frac{5}{7}\cdot \frac{1}{6}=\frac{5}{42}$  

$\frac{{\sout{4}}^1}{{\sout{9}}^3}\cdot \frac{{\sout{15}}^5}{{\sout{16}}^4}=\frac{5}{12}$  

$\frac{3}{{\sout{10}}^2}\cdot \frac{{\sout{15}}^3}{32}=\frac{9}{64}$  

Uzupełniamy tabelę:

a	$\frac{4}{5}$	$\frac{8}{15}$	$2\frac{1}{2}$	$2\frac{1}{7}$	$\frac{5}{7}$	$\frac{4}{9}$	$\frac{3}{10}$
b	$\frac{12}{15}$	$\frac{5}{36}$	$3\frac{1}{3}$	$5\frac{3}{5}$	$\frac{1}{6}$	$\frac{15}{16}$	$\frac{15}{32}$
$\text{a}\cdot \text{b}$	$\frac{16}{25}$	$\frac{2}{27}$	$8\frac{1}{3}$	$12$	$\frac{5}{42}$	$\frac{5}{12}$	$\frac{9}{64}$