Łączymy punkty. 

Długości odcinków obliczamy korzystając z twierdzenia Pitagorasa.

$\left|AF\right|=\left|FB\right|$  

${\left|AF\right|}^2=2^2+2^2$  

${\left|AF\right|}^2=4+4$  

${\left|AF\right|}^2=8$  

$\left|AF\right|=\sqrt{8}$  

$\left|AE\right|=\left|EB\right|$  

${\left|AE\right|}^2=1^2+2^2$  

${\left|AE\right|}^2=1+4$  

${\left|AE\right|}^2=5$  

$\left|AE\right|=\sqrt{5}$  

$\left|AD\right|=\left|DB\right|$  

${\left|AD\right|}^2=2^2+3^2$  

${\left|AD\right|}^2=4+9$  

${\left|AD\right|}^2=13$  

$\left|AD\right|=\sqrt{13}$  

$\left|AC\right|=\left|CB\right|$  

${\left|AC\right|}^2=2^2+5^2$  

${\left|AC\right|}^2=4+25$  

${\left|AC\right|}^2=29$  

$\left|AC\right|=\sqrt{29}$  

 

$\left|AE\right|=\left|BE\right|$          $\left|AF\right|=\left|BF\right|$  

$\left|AD\right|=\left|BD\right|$         $\left|AC\right|=\left|BC\right|$  

$\left|AC\right|>\left|BD\right|$          $\left|AD\right|<\left|BC\right|$