$\sqrt{6}\approx 2\text{poniewaz˙}\sqrt{4}=2\text{a}\sqrt{9}=3$  

$\sqrt{13}\approx 4\text{poniewaz˙}\sqrt{9}=3\text{a}\sqrt{16}=4$  

$\sqrt{45}\approx 7\text{poniewaz˙}\sqrt{36}=6\text{a}\sqrt{49}=7$  

$\sqrt[3]{4}\approx 2\text{poniewaz˙}\sqrt[3]{1}=1\text{a}\sqrt[3]{8}=2$  

$\sqrt[3]{21}\approx 3\text{poniewaz˙}\sqrt[3]{8}=2\text{a}\sqrt[3]{27}=3$  

$\sqrt[3]{99}\approx 5\text{poniewaz˙}\sqrt[3]{64}=4\text{a}\sqrt[3]{125}=5$