POZIOM A

a)  $\sqrt{9}=3\text{, bo}3\cdot 3=9$  

b)  $\sqrt{121}=11\text{, bo}11\cdot 11=121$  

c)  $\sqrt{10000}=100\text{, bo}100\cdot 100=10000$

d) $\sqrt{81}=9\text{, bo}9\cdot 9=81$   

e)  $\sqrt{64}=8\text{, bo}8\cdot 8=64$  

f)  $\sqrt{144}=12\text{, bo}12\cdot 12=144$  

g)  $\sqrt{2500}=50\text{, bo}50\cdot 50=2500$  

h)  $\sqrt{169}=13\text{, bo}13\cdot 13=169$  

 

POZIOM B

a)  $\sqrt{\frac{1}{16}}=\frac{1}{4}\text{, bo}\frac{1}{4}\cdot \frac{1}{4}=\frac{1}{16}$  

b)  $\sqrt{\frac{1}{25}}=\frac{1}{5}\text{, bo}\frac{1}{5}\cdot \frac{1}{5}=\frac{1}{25}$

c) $\sqrt{\frac{9}{25}}=\frac{3}{5}\text{, bo}\frac{3}{5}\cdot \frac{3}{5}=\frac{9}{25}$

d) $\sqrt{\frac{4}{49}}=\frac{2}{7}\text{, bo}\frac{2}{7}\cdot \frac{2}{7}=\frac{4}{49}$    

e)  $\sqrt{\frac{36}{121}}=\frac{6}{11}\text{, bo}\frac{6}{11}\cdot \frac{6}{11}=\frac{36}{121}$  

f)  $\sqrt{\frac{49}{100}}=\frac{7}{10}\text{, bo}\frac{7}{10}\cdot \frac{7}{10}=\frac{49}{100}$

g)   $\sqrt{\frac{81}{144}}=\frac{9}{12}\text{, bo}\frac{9}{12}\cdot \frac{9}{12}=\frac{81}{144}$  

h)  $\sqrt{\frac{64}{100}}=\frac{8}{10}\text{, bo}\frac{8}{10}\cdot \frac{8}{10}=\frac{64}{100}$  

 

POZIOM C

a)  $\sqrt{1\frac{9}{16}}=\sqrt{\frac{25}{16}}=\frac{5}{4}=1\frac{1}{4}\text{, bo}\frac{5}{4}\cdot \frac{5}{4}=\frac{25}{16}=1\frac{9}{16}$  

b)  $\sqrt{2\frac{1}{4}}=\sqrt{\frac{9}{4}}=\frac{3}{2}=1\frac{1}{2}\text{, bo}\frac{3}{2}\cdot \frac{3}{2}=\frac{9}{4}=2\frac{1}{4}$  

c)  $\sqrt{2\frac{2}{49}}=\sqrt{\frac{100}{49}}=\frac{10}{7}=1\frac{3}{7}\text{, bo}\frac{10}{7}\cdot \frac{10}{7}=\frac{100}{49}=2\frac{2}{49}$  

d)  $\sqrt{3\frac{1}{16}}=\sqrt{\frac{49}{16}}=\frac{7}{4}=1\frac{3}{4}\text{, bo}\frac{7}{4}\cdot \frac{7}{4}=\frac{49}{16}=3\frac{1}{16}$  

e)  $\sqrt{5\frac{19}{25}}=\sqrt{\frac{144}{25}}=\frac{12}{5}=2\frac{2}{5}\text{, bo}\frac{12}{5}\cdot \frac{12}{5}=\frac{144}{25}=5\frac{19}{25}$  

f)  $\sqrt{6\frac{1}{4}}=\sqrt{\frac{25}{4}}=\frac{5}{2}=2\frac{1}{2}\text{, bo}\frac{5}{2}\cdot \frac{5}{2}=\frac{25}{4}=6\frac{1}{4}$  

g)  $\sqrt{2\frac{7}{9}}=\sqrt{\frac{25}{9}}=\frac{5}{3}=1\frac{2}{3}\text{, bo}\frac{5}{3}\cdot \frac{5}{3}=\frac{25}{9}=2\frac{7}{9}$  

h)  $\sqrt{2\frac{9}{36}}=\sqrt{\frac{81}{36}}=\frac{9}{6}=\frac{3}{2}=1\frac{1}{2}\text{, bo}\frac{9}{6}\cdot \frac{9}{6}=\frac{81}{36}=2\frac{9}{36}$  

 

POZIOM D

a)  $\sqrt{0,04}=\sqrt{\frac{4}{100}}=\frac{2}{10}=\frac{1}{5}\text{, bo}\frac{2}{10}\cdot \frac{2}{10}=\frac{4}{100}=0,04$

b) $\sqrt{0,64}=\sqrt{\frac{64}{100}}=\frac{8}{10}=\frac{4}{5}\text{, bo}\frac{8}{10}\cdot \frac{8}{10}=\frac{64}{100}=0,64$    

c)  $\sqrt{6,25}=\sqrt{\frac{625}{100}}=\frac{25}{10}=\frac{5}{2}=2\frac{1}{2}\text{, bo}\frac{25}{10}\cdot \frac{25}{10}=\frac{625}{100}=6,25$  

d)  $\sqrt{2,25}=\sqrt{\frac{225}{100}}=\frac{15}{10}=\frac{3}{2}=1\frac{1}{2}\text{, bo}\frac{15}{10}\cdot \frac{15}{10}=\frac{225}{100}=2,25$

e) $\sqrt{1,44}=\sqrt{\frac{144}{100}}=\frac{12}{10}=\frac{6}{5}=1\frac{1}{5}\text{, bo}\frac{12}{10}\cdot \frac{12}{10}=\frac{144}{100}=1,44$   

f)  $\sqrt{0,0144}=\sqrt{\frac{144}{10000}}=\frac{12}{100}=\frac{6}{50}=\frac{3}{25}\text{, bo}\frac{12}{100}\cdot \frac{12}{100}=\frac{144}{10000}=0,0144$  

g)  $\sqrt{0,01}=\sqrt{\frac{1}{100}}=\frac{1}{10}\text{, bo}\frac{1}{10}\cdot \frac{1}{10}=\frac{1}{100}=0,01$  

h)  $\sqrt{0,0009}=\sqrt{\frac{9}{10000}}=\frac{3}{100}\text{, bo}\frac{3}{100}\cdot \frac{3}{100}=\frac{9}{10000}=0,0009$