$\frac{{\sout{2}}^1}{{\sout{3}}^1}\cdot \frac{{\sout{9}}^3}{{\sout{10}}^5}=\frac{3}{5}$

 

$\frac{8}{15}\cdot 2\frac{1}{2}=\frac{{\sout{8}}^4}{{\sout{15}}^3}\cdot \frac{{\sout{5}}^1}{{\sout{2}}^1}=\frac{4}{3}=1\frac{1}{3}$ $\frac{8}{15}\cdot 2\frac{1}{2}=\frac{{\sout{8}}^4}{{\sout{15}}^3}\cdot \frac{{\sout{5}}^1}{{\sout{2}}^1}=\frac{4}{3}=1\frac{1}{3}$

 

$8\text{i}2\text{skracam przez}2$  

$15\text{i}5\text{skracam przez}5$  

 

$\frac{3}{8}\cdot 1\frac{1}{5}=\frac{3}{{\sout{8}}^4}\cdot \frac{{\sout{6}}^3}{5}=\frac{3}{4}\cdot \frac{3}{5}=\frac{9}{20}$

$8\text{i}6\text{skracam przez}2$