$a)\{\begin{array}{l}0,5\left(x-1\right)=\frac{1}{2}y-3\\ y-5=\frac{1}{3}x+2\end{array}$ $a)\{\begin{array}{l}0,5\left(x-1\right)=\frac{1}{2}y-3\\ y-5=\frac{1}{3}x+2\end{array}$  

$b)\{\begin{array}{l}3x+{50}^o=10y+x+{10}^o\\ x+y=5y-\frac{1}{3}x\end{array}$