Zakładamy, że:

$\alpha <\beta$

a) rysunek:

$\sin \alpha =\cos \beta =\frac{9}{15}$

$\cos \alpha =\sin \beta =\frac{12}{15}$

$\mathrm{tg}\alpha =\mathrm{ctg}\beta =\frac{9}{12}$

$\mathrm{ctg}\alpha =\mathrm{tg}\beta =\frac{12}{9}$

 

 

b) rysunek:

$\sin \alpha =\cos \beta =\frac{2}{\sqrt{13}}$

$\cos \alpha =\sin \beta =\frac{3}{\sqrt{13}}$

$\mathrm{tg}\alpha =\mathrm{ctg}\beta =\frac{2}{3}$

$\mathrm{ctg}\alpha =\mathrm{tg}\beta =\frac{3}{2}$

 

 

c) rysunek: 

$\sin \alpha =\cos \beta =\frac{1}{\sqrt{10}}$

$\cos \alpha =\sin \beta =\frac{3}{\sqrt{10}}$

$\mathrm{tg}\alpha =\mathrm{ctg}\beta =\frac{1}{3}$

$\mathrm{ctg}\alpha =\mathrm{tg}\beta =3$