$A=\underset{\left(\text{20 razy}\right)}{\left(\frac{7}{35}+\frac{7}{35}+\dots +\frac{7}{35}+\frac{7}{35}\right)}={\sout{20}}^4\cdot \frac{7}{{\sout{35}}^7}=4\cdot \frac{7}{7}=4\cdot 1=4$ $A=\underset{\left(\text{20 razy}\right)}{\left(\frac{7}{35}+\frac{7}{35}+\dots +\frac{7}{35}+\frac{7}{35}\right)}={\sout{20}}^4\cdot \frac{7}{{\sout{35}}^7}=4\cdot \frac{7}{7}=4\cdot 1=4$

$B=\underset{\left(\text{35 razy}\right)}{\left(\frac{4}{36}+\frac{4}{36}+\dots +\frac{4}{36}+\frac{4}{36}\right)}=\frac{4}{36}\cdot 35=\frac{1}{9}\cdot 35=\frac{35}{9}=3\frac{8}{9}$

 

$A>B$