I gimnazjum

Matematyka na czasie! 1

Każda liczba ujemna podniesiona do nieparzystej potęgi daje w wyniku liczbę ujemną, zatem:

0,83&lt;1 0,89&lt;1

(74)8=74⋅8=732

Obliczamy wartości wyrażeń I, II i III. I. 327<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='1.08em' viewBox='0 0 400000 1080' preserveAspectRatio='xMinYMin slice'><path d='M95,702
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M834 80h400000v40h-400000z'/></svg>​9<svg xmlns="http://www.w3.org/2000/svg" width='400em' height='1.08em' viewBox='0 0 400000 1080' preserveAspectRatio='xMinYMin slice'><path d='M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
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c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M834 80h400000v40h-400000z'/></svg>​​=33​=1

800ha=800⋅100a=80000a=80000⋅100m2=8000000⋅1m⋅1m=

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