$a\text{)}{\sout{15}}^3\cdot \frac{7}{{\sout{10}}^2}=3\cdot \frac{7}{2}=\frac{21}{2}=10\frac{1}{2}$

$b\text{)}\frac{17}{{\sout{26}}^2}\cdot {\sout{13}}^1=\frac{17}{2}\cdot 1=8\frac{1}{2}$

$c\text{)}{\sout{30}}^{10}\cdot \frac{29}{{\sout{33}}^{11}}=10\cdot \frac{29}{11}=\frac{290}{11}=26\frac{4}{11}$