$a)\left(7+3\cdot 2^2\right)-\left(13-3\cdot 4\right)=\left(7+3\cdot 4\right)-\left(13-12\right)=\left(7+12\right)-1=19-1=18$

$b){\left(3\frac{1}{3}\right)}^2-0,75\cdot 8+0,012\cdot {10}^3={\left(\frac{10}{3}\right)}^2-\frac{75}{100}\cdot 8+0,012\cdot 1000=\frac{100}{9}-\frac{3}{4}\cdot 8+12=\frac{100}{9}-\frac{3}{1}\cdot 2+12=11\frac{1}{9}-6+12=5\frac{1}{9}+12=17\frac{1}{9}$

$c)\left(3,2-1\frac{1}{5}\cdot 2\frac{1}{2}\right)\cdot \left(\frac{1}{20}+0,5\cdot 0,9\right)=\left(3,2-\frac{6}{5}\cdot \frac{5}{2}\right)\cdot \left(\frac{5}{100}+0,45\right)=\left(3,2-\frac{6}{2}\right)\cdot \left(0,05+0,45\right)=\left(3,2-3\right)\cdot 0,50=0,2\cdot 0,5=0,10=0,1$

$d)\left(0,4\cdot 10+\frac{2}{5}\cdot 2\right)-\left(2^3\cdot 0,2+0,2\right)=\left(4+\frac{4}{5}\right)-\left(8\cdot 0,2+0,2\right)=4\frac{4}{5}-\left(1,6+0,2\right)=4\frac{8}{10}-1,8=4,8-1,8=3$