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a)[(2a2b3)6⋅(2a2b3)3]:[(2a2b3)2⋅(2a2b3)5]=[(26⋅a2⋅6⋅b3⋅6)⋅(23⋅a2⋅3⋅b3⋅3]:[(22⋅a2⋅2⋅b3⋅2)⋅(25⋅a2⋅5⋅b3⋅5)]=[26⋅a12⋅b18⋅23⋅a6⋅b9]:[22⋅a4⋅b6⋅25⋅a10⋅b15]=
[26+3a12+6b18+9]:[22+5a4+10b6+15]=29⋅a18⋅b27:27⋅a14⋅b21=29−7⋅a18−14⋅b27−21=22⋅a4⋅b6=4⋅a4⋅b6
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