$\frac{( 1 \frac{1}{3} ) ^{2} + ( - 1 \frac{1}{2} ) ^{2}}{\frac{29}{6 ^{2}}} = \frac{( \frac{4}{3} ) ^{2} + ( - \frac{3}{2} ) ^{2}}{\frac{29}{36}} = \frac{\frac{16}{9} + \frac{9}{4}}{\frac{29}{36}} = (1 \frac{7}{9} + 2 \frac{1}{4}) : \frac{29}{36} = (1 \frac{28}{36} + 2 \frac{9}{36}) \cdot \frac{36}{29} = 3 \frac{37}{36} \cdot \frac{36}{29} = 4 \frac{1}{36} \cdot \frac{36}{29} = \frac{145}{36} \cdot \frac{36}{29} = \frac{145}{1} \cdot \frac{1}{29} = \frac{145}{29} = 5$

$\frac{( 2 \frac{1}{2} ) ^{3} - ( 3 \frac{1}{4} ) ^{2}}{\frac{162}{2 ^{5}}} = \frac{( \frac{5}{2} ) ^{3} - ( \frac{13}{4} ) ^{2}}{\frac{162}{32}} = \frac{\frac{125}{8} - \frac{169}{16}}{\frac{81}{16}} = (\frac{250}{16} - \frac{169}{16}) \cdot \frac{16}{81} = \frac{81}{16} \cdot \frac{16}{81} = 1$

$\frac{\frac{92}{25 ^{2}}}{( \frac{3}{5} ) ^{2}} + (\frac{1}{5 ^{3}})) = \frac{\frac{92}{625}}{\frac{9}{25} + \frac{1}{125}} = \frac{\frac{92}{625}}{\frac{45}{125} + \frac{1}{125}} = \frac{\frac{92}{625}}{\frac{46}{125}} = \frac{92}{625} \cdot \frac{125}{46} = \frac{2}{5} \cdot \frac{1}{1} = \frac{2}{5} = 0, 4$

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I-C II-B III-A

Najwygodniejszy sposób nauki z edukacyjnym Odrabiamy AI

4

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