Rozwiązanie:

a) 

$C{H}_{3}COOH+NaOH\to C{H}_{3}COONa+H_{2}O$

$2C{H}_{3}COOH+2Na\to 2C{H}_{3}COONa+H_2\uparrow$

$2C{H}_{3}COOH+N{a}_{2}O\to 2C{H}_{3}COONa+H_{2}O$

b) 

$2HCOOH+Ca{\left(OH\right)}_2\to {\left(HCOO\right)}_{2}Ca+2H_{2}O$

$2HCOOH+Ca\to {\left(HCOO\right)}_{2}Ca+H_2\uparrow$

$2HCOOH+Ca{O}_{}\to {\left(HCOO\right)}_{2}Ca+H{}_{2}O$

c) 

$2C_3{H}_{7}COOH+2K\to 2C_{3}HCOOK+H_2\uparrow$

$C_3{H}_{7}COOH+KOH\to C_3{H}_{7}COOK+H_{2}O$

${2C}_3{H}_{7}COOH+K_{2}O\to 2C_3{H}_{7}COOK+H_{2}O$

d) 

$2C{H}_{3}COOH+Mg{\left(OH\right)}_2\to {\left(C{H}_{3}COO\right)}_{2}Mg+2H_{2}O$

$2C{H}_{3}COOH+Mg{O}_{}\to {\left(C{H}_{3}COO\right)}_{2}Mg+H_{2}O$

$2C{H}_{3}COOH+Mg\to {\left(C{H}_{3}COO\right)}_{2}Mg+H_2\uparrow$

e) 

$2C_2{H}_{5}COOH+Ba\to {\left(C_2{H}_{5}COO\right)}_{2}Ba+H_2\uparrow$

$2C_2{H}_{5}COOH+Ba{\left(OH\right)}_2\to {\left(C_2{H}_{5}COO\right)}_{2}Ba+2H_{2}O$

$2C_2{H}_{5}COOH+BaO\to {\left(C_2{H}_{5}COO\right)}_{2}Ba+H_{2}O$

f) 

$6HCOOH+A{l}_2{O}_3\to 2{\left(HCOO\right)}_{3}Al+3H_{2}O$

$6HCOOH+2Al\to {2\left(HCOO\right)}_{3}Al+3H_2\uparrow$

$3HCOOH+Al{\left(OH\right)}_3\to {\left(HCOO\right)}_{3}Al+3H_{2}O$